Advent of Code: Day 3

 Link to problem: https://adventofcode.com/2024/day/3

Oh no... regex. I hate regex. Perplexity is great at regex.

import re

pattern = r"mul\((\d{1,3}),\s*(\d{1,3})\)"

matches = re.findall(pattern, input)

print(matches)

Thanks Perplexity!

sum = 0

for a,b in matches:

product = int(a) * int(b)

sum += product

print(sum)

That's problem 1 done.

Now... for problem 2:

pattern = r"mul\(\d{1,3},\s?\d{1,3}\)|do\(\)|don't\(\)"

matches = re.findall(pattern, input)

print(matches)

Thanks again Perplexity!

do = True

sum = 0

for i in matches:

if i == 'do()':

do = True

continue

if i == "don't()":

do = False

continue

if do:

a,b = i.lstrip('mul(').rstrip(')').split(',')

product = int(a) * int(b)

sum += product

print(sum)

This one felt like cheating... I'll come back to do this in some terrible language or just do the string processing manually.

Answers : 156388521, 75920122